求助！阳历和阴历的转换问题
今天初一，先拜个年再说！
阳历是怎样转换成阴历的？我实在搞不懂！唉！
可否给出算法，或者最好给我个控件，能用就好！
多谢！
问题点数：100、回复次数：3Top
1 楼pazee（耙子)(今年过年不收礼，收礼只收尿不湿）回复于 2003-02-02 01:06:14 得分 50
你搜索一下从前的帖子吧，无数篇。Top
2 楼plainsong（短歌)(）回复于 2003-02-02 11:14:27 得分 20
没有直接转换的算法，需要转换数据。
好久没来了，pazee都两个星了！恭喜恭喜！Top
3 楼shally5（我在一旁静静的看着你）回复于 2003-02-02 12:43:41 得分 30
转
农历与公历问题,怎样由公历换算出农历的月份与日子
算了，我贴出来吧！
完全是标准的c函数，不过我在vc下写的，。相信移植没问题。
另外，我还用php写了一遍。
/*************************************************
计算阴历日期
范围从2000/02/05开始的20年
代码实现：耙子 2001/08/17
最后修订： 2001/08/18
**************************************************/
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>
typedef unsigned int DWORD;
/**************************************************
sLunar: 返回阴历日期字符串
dwDays: 所求日期距离 2000/02/05的天数差
**************************************************/
void Lunar2Solar(char *sLunar, const DWORD dwDays)
{
const char sTG[][3]= {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
const char sDZ[][3]= {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};
const char sSX[][3]= {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"};
const char sMon[][3]= {"正","二","三","四","五","六","七","八","九","十","冬","腊"};
const char sDate[][5]= {
"初一","初二","初三","初四","初五","初六","初七","初八","初九","初十",
"十一","十二","十三","十四","十五","十六","十七","十八","十九","二十",
"廿一","廿二","廿三","廿四","廿五","廿六","廿七","廿八","廿九","三十"
};
// Start from 2000/2/5, 20 Lunar years' Data
const DWORD dwLunarYears= 20;
const DWORD dwCalendarData[]=
{
0xc96, // 0000 0000 1100 1001 0110
0x41a95, // 0100 0001 1010 1001 0101
0xd4a, // 0000 0000 0100 1101 1010
0xda5,
0x20b55,
0x56a,
0x7155b,
0x25d,
0x92d,
0x5192b,
0xa95,
0xb4a,
0x416aa,
0xad5,
0x90ab5,
0x4ba,
0xa5b,
0x60a57,
0x52b,
0xa93,
0x40e59
};
DWORD i, j;
DWORD yy=0, mm=0;
DWORD t, r, m, p=0, q;
for (i=0; i< dwLunarYears; i++)
{
t= dwCalendarData[i];
r= (t >> 16) & 0x0f;
m= (r==0)?12:13;
for (j=0; j<m; j++)
{
q= ((t >> (m-j-1)) & 1)==0 ? 29 : 30;
if (p+q > dwDays)
break;
p+= q;
}
if (j < m)
break;
}
// Date Overflow
if (i == dwLunarYears)
{
sprintf(sLunar, "%s", "I don't know so much!");
return;
}
sprintf(
sLunar,
"%s%s年(%s) %s%s月%s",
sTG[(i+6)%10], // Heavenly stemas
sDZ[(i+4)%12], // Earthly Branches
sSX[(i+4)%12], // Shu xing
(((r!=0) && (j == r)) ? "闰" : ""), // Leap month
sMon[((r!=0) && (j > r-1)) ? j-1 : j],
sDate[dwDays-p]
);
return;
}
// 测试代码
int main ()
{
time_t t1, t2;
struct tm tt;
DWORD dwDiffTime;
char sLunar[32];
tt.tm_year= 2000-1900;
tt.tm_mon=1;
tt.tm_mday=5;
tt.tm_hour=0;
tt.tm_min=0;
tt.tm_sec=0;
t1= mktime(&tt);
for (int i=0; i< 365; i++ ) {
tt.tm_year= 2030-1900;
tt.tm_mon=0;
tt.tm_mday=i;
tt.tm_hour=0;
tt.tm_min=0;
tt.tm_sec=0;
t2= mktime(&tt);
printf("%s", ctime(&t2));
dwDiffTime= difftime(t2,t1) / (60*60*24);
printf("起第 %d 天 ", dwDiffTime);
Lunar2Solar(sLunar, dwDiffTime);
puts(sLunar);
}
getch();
return 0;
}
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