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Listbox 拖放的问题！解决就给100分！

stwx 2003-03-12 08:00:01

listbox中有多个item, 一个对像拖放到一个listbox,
在listbox 的事件

List1_DragDrop(Source As Control, X As Single, Y As Single) 中

如何由X，Y得到拖放到listbox 的那个 list.ListIndex，要用API吗？

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northwolves 2003-03-14

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Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" _
(ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, _
lParam As Any) As Long
Private Const LB_ITEMFROMPOINT = &H1A9

Private Sub Form_Load()
Dim i As Long
For i = 1 To 100
List1.AddItem i
Next
Text1.Text = "aaaa"'dragmode=1
Text2 = "bbbb"'dragmode=1
Text3 = "cccc"'dragmode=1
End Sub

Private Sub List1_DragDrop(Source As Control, X As Single, Y As Single)
Dim lXPoint As Long, lYPoint As Long, lIndex As Long
lXPoint = CLng(X / Screen.TwipsPerPixelX)
lYPoint = CLng(Y / Screen.TwipsPerPixelY)
If TypeOf Source Is TextBox Then lIndex = SendMessage(List1.hwnd, LB_ITEMFROMPOINT, 0, _
ByVal ((lYPoint * 65536) + lXPoint)) ' 获得当前的光标所在的的屏幕位置
List1.AddItem Source.Text, lIndex
End Sub

stwx 2003-03-13

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我没弄过这些，谢谢了。100分请笑纳

northwolves 2003-03-13

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奇怪。

Dim lXPoint As Long
Dim lYPoint As Long
Dim lIndex As Long
lXPoint = CLng(X / Screen.TwipsPerPixelX)
lYPoint = CLng(Y / Screen.TwipsPerPixelY)
lIndex = SendMessage(List1.hwnd, LB_ITEMFROMPOINT, 0, _
ByVal ((lYPoint * 65536) + lXPoint))
MsgBox List1.List(lIndex)

stwx 2003-03-13

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to :northwolves(野性的呼唤

lYPoint 和 lXPoint 不用给值吗？我何我的 LINDEX 总是0 因为lYPoint 和 lXPoint都是0 ，怎办

northwolves 2003-03-13

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Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" _
(ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, _
lParam As Any) As Long

Private Const LB_ITEMFROMPOINT = &H1A9

Dim lXPoint As Long
Dim lYPoint As Long
Dim lIndex As Long
LINDEX = SendMessage(List1.hwnd, LB_ITEMFROMPOINT, 0, _
ByVal ((lYPoint * 65536) + lXPoint))
MsgBox List1.List(LINDEX)

stwx 2003-03-13

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to :northwolves(野性的呼唤

你的代码出现 "DLL 调用约定错误"，如何解决？ lYpoint 和 lXPoint 为何值？

其它各位方法并不可取

gang75 2003-03-12

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northwolves 2003-03-12

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Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" _
(ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, _
lParam As Any) As Long

Private Const LB_ITEMFROMPOINT = &H1A9
Dim LINDEX As Long
LINDEX = SendMessage(List1.hwnd, LB_ITEMFROMPOINT, 0, _
ByVal ((lYPoint * 65536) + lXPoint))
MsgBox List1.List(LINDEX)

xixixi9988 2003-03-12

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应该很简单：List1.ListIndex = Y / Me.TextHeight ("A")

bobob 2003-03-12

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是否可以用焦点来考虑？拖放的目的地应该具有焦点，再用api得到当前焦点的句柄~仅供参考

stephenlv 2003-03-12

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这个我刚刚做过。
可以对list进行划分，计算得到一个数组。数组的每一个项对应于list的每一项。这样可以自己编一个函数来测试鼠标所在点是否在你想要的区域里，这样，就可以得到数组的index，进而知道list的当前index，使用index＋list.topindex则可以得到相应的list.listindex
自定义类型：
type Point
x as single
y as single
end type

type Rect
point1 as Point
point2 as point
end type

dim m_Rects(dimension) as Rect'dimension为和list中可视的项目数相等。