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northwolves 2004-07-12
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呵呵，好象错了：
log(a^(1/n))=(1/n)*log(a)-------------->a^(1/n)=exp((1/n)*log(a))
log(a^(1/n))=(1/n)*log(a)-------------->a^(1/n)=exp((1/n)*log(a))
northwolves 2004-07-12
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估计计算机是通过转化为对数进行运算。
log(a^(1/n))=log(a)-log(n)-------------->a^(1/n)=exp(log(a)-log(n))
log(a^(1/n))=log(a)-log(n)-------------->a^(1/n)=exp(log(a)-log(n))
sanyou98 2004-07-12
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up
华芸智森 2004-07-12
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A^(1/N)
tztz520 2004-07-12
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Private Sub Command1_Click()
Dim a As Long
a = 2
MsgBox a ^ 3
End Sub
Dim a As Long
a = 2
MsgBox a ^ 3
End Sub
