oracle中是否有可將數字轉為二進制的涵數或方法!!!!
oracle中是否有可將數字轉為二進制的涵數或方法!!!! 问题点数：0、回复次数：3Top
1 楼JeromeLiu（烛光）回复于 2004-09-04 13:50:53 得分 0
好像没有的Top
2 楼beckhambobo（beckham）回复于 2004-09-04 15:08:45 得分 0
create or replace function to_base( p_dec in number, p_base in number )
return varchar2
is
l_str varchar2(255) default NULL;
l_num number default p_dec;
l_hex varchar2(16) default '0123456789ABCDEF';
begin
if ( p_dec is null or p_base is null )
then
return null;
end if;
if ( trunc(p_dec) <> p_dec OR p_dec < 0 ) then
raise PROGRAM_ERROR;
end if;
loop
l_str := substr( l_hex, mod(l_num,p_base)+1, 1 ) || l_str;
l_num := trunc( l_num/p_base );
exit when ( l_num = 0 );
end loop;
return l_str;
end to_base;
/
create or replace function to_dec
( p_str in varchar2,
p_from_base in number default 16 ) return number
is
l_num number default 0;
l_hex varchar2(16) default '0123456789ABCDEF';
begin
if ( p_str is null or p_from_base is null )
then
return null;
end if;
for i in 1 .. length(p_str) loop
l_num := l_num * p_from_base + instr(l_hex,upper(substr(p_str,i,1)))-1;
end loop;
return l_num;
end to_dec;
/
show errors
create or replace function to_hex( p_dec in number ) return varchar2
is
begin
return to_base( p_dec, 16 );
end to_hex;
/
create or replace function to_bin( p_dec in number ) return varchar2
is
begin
return to_base( p_dec, 2 );
end to_bin;
/
create or replace function to_oct( p_dec in number ) return varchar2
is
begin
return to_base( p_dec, 8 );
end to_oct;
/
how to use them:
SQL> select to_bin( 123 ) bin, to_hex( 123 ) hex, to_oct( 123 ) oct from dual
2 /
BIN HEX OCT
--------------- --------------- ---------------
1111011 7B 173
SQL>
SQL> select to_dec( '1111011', 2 ) base2, to_dec( '7B' ) base16,
2 to_dec('173',8) base8
3 from dual
4 /
BASE2 BASE16 BASE8
---------- ---------- ----------
123 123 123
Top
3 楼chen_cyh（figer）回复于 2004-10-09 13:55:58 得分 0
好，收藏！Top
