又一个向数据库中添加记录的问题!!!!:(三天了还没解决。。。。
String rwbh=(String)request.getParameter("rwbh");
String rwnr=new String(request.getParameter("RWNR").getBytes("ISO8859_1"));
String fbrbm =(String)session.getAttribute("wjhb_userid");
String[] sql = new String[2];
sql[0]="insert into wjhb_taskinfo(RWBH,RWNR,FBRBM,FBSJ,RQS,HFS,SJBH) values(SEQ_WJHB_RWBH.NEXTVAL,'"+rwnr+"','"+fbrbm+"',sysdate,'0','0','"+rwbh+"')";
sql[1]="update wjhb_taskinfo set HFS=HFS+1 ,HFRBM_END='"+fbrbm +"',HFSJ_END = sysdate where RWBH="+rwbh;
用的是上面两条SQL语句,单独在PLSQL里试过了,没有语法错误。。。,但在JSP页面里,当写了内容按发布按钮后,总会出先下面的错误:
exception
org.apache.jasper.JasperException
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:372)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause
java.lang.NullPointerException
org.apache.jsp.saveHfnr2_jsp._jspService(saveHfnr2_jsp.java:58)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
(NullPointerException————》空指针??)
哪位大哥知道的,帮忙分析一下,谢谢你了。。。
问题点数:10、回复次数:4Top
1 楼usaspy(行走的鱼)回复于 2005-06-02 14:59:41 得分 4
String rwbh=(String)request.getParameter("rwbh");
String rwnr=new String(request.getParameter("RWNR").getBytes("ISO8859_1"));
String fbrbm =(String)session.getAttribute("wjhb_userid");
以上的值有为null的。Top
2 楼pejastojakovic(佩贾)回复于 2005-06-02 15:02:35 得分 2
空指针应该不是sql的语法错误。应该看看你连接数据库的类是不是有问题或者配置是否正确。Top
3 楼chuanyuan88(船员-逆水行舟,不进则退!)回复于 2005-06-02 15:09:29 得分 4
上面的几个成员变量都有输出值么?打印出来看看Top
4 楼ortegasl(假如不是程序员)回复于 2005-06-02 15:30:38 得分 0
多谢各位,问题已解决,RWNR是空值,原来大小写也有关系:(Top




