加了WITH ENCRYPTION的存储过程被破解还原的可能性有多高﹖
我想知道加了WITH ENCRYPTION的存储过程被破解还原的可能性有多高﹖
是不是有这种可能呢﹖
有这种工具吗﹖
最好是没有办法！
各位知道吗﹖
问题点数：20、回复次数：4Top
1 楼liujiayu10（活着就好）回复于 2005-08-03 09:24:04 得分 0
学习，同时帮你顶！Top
2 楼vivianfdlpw（）回复于 2005-08-03 09:31:12 得分 10
网上搜索：解密 WITH ENCRYPTIONTop
3 楼xueguang（xg）回复于 2005-08-03 09:40:25 得分 10
可能性是百分之百,以下是个破解过程
drop proc sp_decrypt
go
create PROCEDURE sp_decrypt(@objectname varchar(50))
AS
begin
set nocount on
--CSDN：j9988 copyright:2004.07.15
--V3.2
--破解字节不受限制，适用于SQLSERVER2000存储过程，函数，视图，触发器
--修正上一版"视图触发器"不能正确解密错误
--发现有错，请E_MAIL：CSDNj9988@tom.com
begin tran
declare @objectname1 varchar(100),@orgvarbin varbinary(8000)
declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)
DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
declare @i int,@status int,@type varchar(10),@parentid int
declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int
select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@objectname)
create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)
insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectname)
select @number=max(number) from #temp
set @k=0
while @k<=@number
begin
if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)
begin
if @type='P'
set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectname +';'+rtrim(@k)+' WITH ENCRYPTION AS '
else 'ALTER PROCEDURE '+ @objectname+' WITH ENCRYPTION AS '
end)
if @type='TR'
begin
declare @parent_obj varchar(255),@tr_parent_xtype varchar(10)
select @parent_obj=parent_obj from sysobjects where id=object_id(@objectname)
select @tr_parent_xtype=xtype from sysobjects where id=@parent_obj
if @tr_parent_xtype='V'
begin
set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF INSERT AS PRINT 1 '
end
else
begin
set @sql1='ALTER TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '
end
end
if @type='FN' or @type='TF' or @type='IF'
set @sql1=(case @type when 'TF' then
'ALTER FUNCTION '+ @objectname+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '
when 'FN' then
'ALTER FUNCTION '+ @objectname+'(@a char(1)) returns char(1) with encryption as begin return @a end'
when 'IF' then
'ALTER FUNCTION '+ @objectname+'(@a char(1)) returns table with encryption as return select @a as a'
end)
if @type='V'
set @sql1='ALTER VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'
set @q=len(@sql1)
set @sql1=@sql1+REPLICATE('-',4000-@q)
select @sql2=REPLICATE('-',8000)
set @sql3='exec(@sql1'
select @colid=max(colid) from #temp where number=@k
set @n=1
while @n<=CEILING(1.0*(@colid-1)/2) and len(@sql3)<=3996
begin
set @sql3=@sql3+'+@'
set @n=@n+1
end
set @sql3=@sql3+')'
exec sp_executesql @sql3,N'@sql1 nvarchar(4000),@ varchar(8000)',@sql1=@sql1,@=@sql2
end
set @k=@k+1
end
set @k=0
while @k<=@number
begin
if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)
begin
select @colid=max(colid) from #temp where number=@k
set @n=1
while @n<=@colid
begin
select @OrigSpText1=ctext,@encrypted=encrypted,@status=status FROM #temp WHERE colid=@n and number=@k
SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectname) and colid=@n and number=@k)
if @n=1
begin
if @type='P'
SET @OrigSpText2=(case when @number>1 then 'CREATE PROCEDURE '+ @objectname +';'+rtrim(@k)+' WITH ENCRYPTION AS '
else 'CREATE PROCEDURE '+ @objectname +' WITH ENCRYPTION AS '
end)
if @type='FN' or @type='TF' or @type='IF'
SET @OrigSpText2=(case @type when 'TF' then
'CREATE FUNCTION '+ @objectname+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '
when 'FN' then
'CREATE FUNCTION '+ @objectname+'(@a char(1)) returns char(1) with encryption as begin return @a end'
when 'IF' then
'CREATE FUNCTION '+ @objectname+'(@a char(1)) returns table with encryption as return select @a as a'
end)
if @type='TR'
begin
if @tr_parent_xtype='V'
begin
set @OrigSpText2='CREATE TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTEAD OF INSERT AS PRINT 1 '
end
else
begin
set @OrigSpText2='CREATE TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR INSERT AS PRINT 1 '
end
end
if @type='V'
set @OrigSpText2='CREATE VIEW '+@objectname+' WITH ENCRYPTION AS SELECT 1 as f'
set @q=4000-len(@OrigSpText2)
set @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)
end
else
begin
SET @OrigSpText2=REPLICATE('-', 4000)
end
SET @i=1
SET @resultsp = replicate(N'A', (datalength(@OrigSpText1) / 2))
WHILE @i<=datalength(@OrigSpText1)/2
BEGIN
SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^
(UNICODE(substring(@OrigSpText2, @i, 1)) ^
UNICODE(substring(@OrigSpText3, @i, 1)))))
SET @i=@i+1
END
set @orgvarbin=cast(@OrigSpText1 as varbinary(8000))
set @resultsp=(case when @encrypted=1
then @resultsp
else convert(nvarchar(4000),case when @status&2=2 then uncompress(@orgvarbin) else @orgvarbin end)
end)
print @resultsp
set @n=@n+1
end
end
set @k=@k+1
end
drop table #temp
rollback tran
end
Top
4 楼frank_lee_cn（Frank）回复于 2005-08-03 16:05:40 得分 0
天啊！老兄也太厉害了吧！
不知道老兄的这个方法在 SQL2005 下还能用否﹖Top
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