各位大侠，php中ip2long，long2ip的2个函数，在java中如何实现？100分
各位大侠，php中ip2long，long2ip的2个函数，在java中如何实现？100分 问题点数：100、回复次数：3Top
1 楼keiy（）回复于 2005-10-09 11:32:27 得分 100
//ip2long
import java.net.*;
public class test {
public static int str2Ip(String ip) throws UnknownHostException {
InetAddress address = InetAddress.getByName(ip);
byte[] bytes = address.getAddress();
int a, b, c, d;
a = byte2int(bytes[0]);
b = byte2int(bytes[1]);
c = byte2int(bytes[2]);
d = byte2int(bytes[3]);
int result = (a << 24) | (b << 16) | (c << 8) | d;
return result;
}
public static int byte2int(byte b) {
int l = b & 0x07f;
if (b < 0) {
l |= 0x80;
}
return l;
}
public static long ip2long(String ip) throws UnknownHostException {
int ipNum = str2Ip(ip);
return int2long(ipNum);
}
public static long int2long(int i) {
long l = i & 0x7fffffffL;
if (i < 0) {
l |= 0x080000000L;
}
return l;
}
public static void main(String[] args) throws Exception {
System.out.println(ip2long("192.168.0.111"));
}
}
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2 楼savage711（）回复于 2005-10-09 11:34:57 得分 0
okTop
3 楼keiy（）回复于 2005-10-09 12:14:36 得分 0
我还没写完你就结帖了,^_^.以下是全部两个函数的程序:
import java.net.*;
public class test {
public static int str2Ip(String ip) throws UnknownHostException {
InetAddress address = InetAddress.getByName(ip);
byte[] bytes = address.getAddress();
int a, b, c, d;
a = byte2int(bytes[0]);
b = byte2int(bytes[1]);
c = byte2int(bytes[2]);
d = byte2int(bytes[3]);
int result = (a << 24) | (b << 16) | (c << 8) | d;
return result;
}
public static int byte2int(byte b) {
int l = b & 0x07f;
if (b < 0) {
l |= 0x80;
}
return l;
}
public static long ip2long(String ip) throws UnknownHostException {
int ipNum = str2Ip(ip);
return int2long(ipNum);
}
public static long int2long(int i) {
long l = i & 0x7fffffffL;
if (i < 0) {
l |= 0x080000000L;
}
return l;
}
public static String long2ip(long ip) {
int [] b=new int[4] ;
b[0] = (int)((ip >> 24) & 0xff);
b[1] = (int)((ip >> 16) & 0xff);
b[2] = (int)((ip >> 8) & 0xff);
b[3] = (int)(ip & 0xff);
String x;
Integer p;
p=new Integer(0);
x=p.toString(b[0])+"."+p.toString(b[1])+"."+p.toString(b[2])+"."+p.toString(b[3]);
return x;
}
public static void main(String[] args) throws Exception {
long ip=ip2long("192.168.0.111");
System.out.println(ip);
System.out.println(long2ip(ip));
}
}
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