如何获得文本框最后一行的内容

paullbm 2005-12-17 07:26:34
如题,本人希望大侠们教小弟用一种最方便、时间复杂度最简单的方法来解决此问题。
最先完成且达到要求者得全分~
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rainstormmaster 2005-12-17
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//这就是最简单的了??

差不多就是这样,原理没错,优化的话,不外乎去掉一些字串处理的函数
paullbm 2005-12-17
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这就是最简单的了??
rainstormmaster 2005-12-17
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就是这样

不过这种方法不适用于richtextbox
northwolves 2005-12-17
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这种方法可识别软回车
northwolves 2005-12-17
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'add a textbox with "multiline=true","scrollbars=2".

Private Declare Function SendMessage Lib "USER32" Alias "SendMessageA" _
(ByVal hWnd As Long, ByVal wMsg As Long, ByVal wParam As Long, _
lParam As Any) As Long
Private Declare Function SendMessageByNum Lib "USER32" _
Alias "SendMessageA" (ByVal hWnd As Long, ByVal wMsg As Long, _
ByVal wParam As Long, ByVal lParam As Long) As Long
Private Declare Function SendMessageByString Lib "USER32" Alias _
"SendMessageA" (ByVal hWnd As Long, ByVal wMsg As Long, ByVal wParam _
As Long, ByVal lParam As String) As Long

Private Const EM_LINEINDEX = &HBB
Private Const EM_GETLINECOUNT = &HBA
Private Const EM_GETLINE = &HC4
Private Const EM_LINELENGTH = &HC1

Function GetLineText(ByVal txtbox As TextBox, ByVal LineIndex As Long) As String '返回指定行的内容
Dim lc As Long, linechar As Long
linechar = SendMessageByNum(txtbox.hWnd, EM_LINEINDEX, LineIndex, 0)
lc = SendMessageByNum(txtbox.hWnd, EM_LINELENGTH, linechar, 0) + 1
GetLineText = String(lc + 2, 0)
Mid(GetLineText, 1, 1) = Chr(lc And &HFF)
Mid(GetLineText, 2, 1) = Chr(lc \ &H100)
lc = SendMessageByString(txtbox.hWnd, EM_GETLINE, LineIndex, GetLineText)
GetLineText = Left(GetLineText, lc)
End Function

Function lastline(ByVal txtbox As TextBox) As String
Dim linecount As Long
linecount = SendMessage(txtbox.hWnd, EM_GETLINECOUNT, 0, 0) - 1 '返回行数
lastline = GetLineText(txtbox, linecount)
End Function


Private Sub Command1_Click()
MsgBox lastline(Text1)
End Sub

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