.NET中使用Ajax的小问题

caibird1984 2007-12-20 03:57:58

小弟最近新学Ajax，遇到这么个问题。假设小弟的Html代码是这样：



<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">

<html>

<head>

<title>Sending Request Data Using GET and POST</title>

<meta name="GENERATOR" content="Microsoft Visual Studio .NET 7.1">

<meta name=ProgId content=VisualStudio.HTML>

<meta name=Originator content="Microsoft Visual Studio .NET 7.1">

<script language="javascript">

var xmlHttp;



function createXMLHttpRequest()

{

	if(window.ActiveXObject)

	{

		xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");

	}

	else if(windo.HTMLHttpRequest)

	{

		xmlHttp = new XMLHttpRequest();

	}

}



function createQueryString()

{

	var firstName = document.getElementById("firstName").value;

	var middleName = document.getElementById("middleName").value;

	var birthday = document.getElementById("birthday").value;

	

	var queryString = "firstname=" + firstName + "&middlename=" + middleName + "&birthday=" + birthday;

	return queryString;

}



function doRequestUsingGET()

{

	createXMLHttpRequest();

	

	var queryString = "WebForm3.aspx?";

	queryString = queryString + createQueryString() + "×tamp=" + new Date().getTime();

	xmlHttp.onreadystatechange = handleStateChange;

	xmlHttp.open("GET",queryString, true);

	xmlHttp.send(null);

}



function doRequestUsingPOST()

{

	createXMLHttpRequest();

	

	var url = "WebForm3.aspx?timeStamp=" + new Date().getTime();

	var queryString = createQueryString();

	

	xmlHttp.open("POST", url, true);

	xmlHttp.onreadystatechange = handleStateChange;

	xmlHttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded;");

	xmlHttp.send(queryString);

}



function handleStateChange()

{

	if(xmlHttp.readyState == 4)

	{

		if(xmlHttp.status == 200)

		{

			parseResult();

		}

	}

}



function parseResult()

{

	var responseDiv = document.getElementById("serverResponse");

	if(responseDiv.hasChildNodes())

	{

		responseDiv.removeChild(responseDiv.childNodes[0]);

	}

	var responseText = document.createTextNode(xmlHttp.responseText);

	responseDiv.appendChild(responseText);

}

</script>

</head>

	<body>

		<h1>Enter your first name, middle name, and birthday:</h1>

		

		<table>

				<tr>

					<td>First Name:</td>

					<td><input type="text" id="firstName"></td>

				</tr>

				<tr>

					<td>Middle Name:</td>

					<td><input type="text" id="middleName"></td>

				</tr>

				<tr>

					<td>Birthday:</td>

					<td><input type="text" id="birthday"></td>

				</tr>

		</table>

		

		<form action="#">

			<input type="button" value="Send parameters using GET" onclick="doRequestUsingGET();">

			<br><br>

			<input type="button" value="Send parameters using POST" onclick="doRequestUsingPOST();">

			<br>

			<h2>Server Response:</h2>

			<div id="serverResponse"></div>

		</form>

	</body>

</html>

服务器端WebForm3.aspx没有HTML代码，.cs代码如下：



private void Page_Load(object sender, System.EventArgs e)

		{

			Response.ContentType = "text/xml";



			string firstName = Request.QueryString["firstname"] != "" ? Request.QueryString["firstname"].ToString() : "";

			string middleName = Request.QueryString["middlename"] != "" ? Request.QueryString["middlename"].ToString() : "";

			string birthday = Request.QueryString["birthday"] != "" ? Request.QueryString["birthday"].ToString() : "";

			string returnValue = "FirstName:" + firstName + ",MiddleName:" + middleName + ",Birthday:"+birthday;



			Response.Write(returnValue);

			Response.Flush();

			Response.Close();

		}

这是我根据某教科书上的例子改的，目的就是在HTML中输入姓名、生日等信息，经过服务器端拼成一个字符穿再返回给前台。不过目前小弟使用GET的方式没有问题，但是使用POST好象不行。书上的例子是JAVA的，因此小弟想请教各位高手，对于POST形式的请求应该怎么解释参数？用什么方式？还请各位不吝赐教，因为这关系到XML请求的问题，所以目前小弟卡在这里了，不胜感激！

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