[严正声明]关于delete built-in型数组可以不带[]的谬论！

/*实在是看不下去了。这几天到处有人说这个。于是转篇文章给大家看看。

有哪一本书说过可以不带[]吗？(C++ Primer/The C++ Programming Language/C++ Standard)

请找出来看看！

[16.13] Can I drop the [] when deleteing array of some built-in type (char, int, etc)?



No! 

Sometimes programmers think that the [] in the delete[] p only exists so the compiler will call the appropriate destructors for all elements in the array. Because of this reasoning, they assume that an array of some built-in type such as char or int can be deleted without the []. E.g., they assume the following is valid code: 





 void userCode(int n)

 {

   char* p = new char[n];

   ...

   delete p;     // ← ERROR! Should be delete[] p !

 } 

But the above code is wrong, and it can cause a disaster at runtime. In particular, the code that's called for delete p is operator delete(void*), but the code that's called for delete[] p is operator delete[](void*). The default behavior for the latter is to call the former, but users are allowed to replace the latter with a different behavior (in which case they would normally also replace the corresponding new code in operator new[](size_t)). If they replaced the delete[] code so it wasn't compatible with the delete code, and you called the wrong one (i.e., if you said delete p rather than delete[] p), you could end up with a disaster at runtime.