C#将二进制小数byte[]型转换成double型，请大家帮帮忙！

           bool flag1 = tmp1[0] == '1';      //符号

             bool flag2 = tmp1[1] == '1';      //指数符号

        //16进制转2进制字符串

        public static string HtoS(int num)

        {

            return Convert.ToString(num, 2).PadLeft(8, '0');

        }

            bool flag2 = tmp1[1] == '1' ? true : false;      //指数符号

 //16进制转2进制字符串

        public static string HtoS(int num)

        {

            string tmp = Convert.ToString(num, 2);             //用来计算符号，指数符号，和指数

            if (tmp.Length < 8)

                tmp = new string('0', 8 - tmp.Length) + tmp;

            return tmp;

        }

public static void Main()

{

 string tmp1 = HtoS(0x03);           

            bool flag1 = tmp1[0] == '1' ? true : false;      //符号

            bool flag2 = tmp1[0] == '1' ? true : false;      //指数符号

            //指数

            int power = Convert.ToInt32(tmp1.Substring(2, 6), 2);

            if (flag2)

                power = 0 - power;



            //小数部分

            string tmp2 = HtoS(0xDF) + HtoS(0xCF);

            double decimal_fraction = 1;            

            for (int i = 0,j=-1; i < 16; ++i,--j)

            {

                decimal_fraction += Convert.ToInt32(tmp2[i].ToString()) * Math.Pow(2, j);

            }

            double result = Math.Pow(decimal_fraction, power);

            if (flag1)

                result = 0 - result;

            Console.WriteLine(result); 

}  

using System;



class Program

{

  static void Main()

  {

    byte[] data = { 0x03,0xDF,0xCF };

    Console.WriteLine(ToSingle3(data, 0));

  }

  

  // 返回由字节数组中指定位置的三个字节转换来的单精度浮点数。

  static float ToSingle3(byte[] value, int startIndex)

  {

    if (value == null) throw(new ArgumentNullException());

    if (startIndex < 0 || startIndex > value.Length - 3) throw(new ArgumentOutOfRangeException());

    double t = 1;                           // 尾数

    double s = 0.5;

    byte b = value[startIndex + 1];

    for (int i = 0; i < 8; i++)

    {

      if ((b & 0x80) != 0) t += s;

      b <<= 1;

      s  /= 2;

    }

    b = value[startIndex + 2];

    for (int i = 0; i < 8; i++)

    {

      if ((b & 0x80) != 0) t += s;

      b <<= 1;

      s  /= 2;

    }

    b = value[startIndex];

    int sign0 = (b & 0x80) == 0 ? 1 : -1;   // 尾数的符号

    int sign1 = (b & 0x40) == 0 ? 1 : -1;   // 指数的符号

    int E = (b & 0x3F) * sign1;             // 指数

    return (float)(Math.Pow(t, E) * sign0);

  }

}

/* 程序输出：

6.583914

*/