2006-12-01到2008-06-20杂遍历之间的日期??????(送高分)

liyanqing_01 2008-07-02 07:52:19

如何他们之间的每天都遍历出来？

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切换为时间正序

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liyanqing_01 2008-07-02

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可以
谢谢

sd5816690 2008-07-02

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两个版本，JAVA和javascript



package src.dyy.superSearch;



import java.util.Calendar;



public class Test1 {



	public static void main(String[] args) {

		Calendar date1 = Calendar.getInstance();

		date1.set(2006, 11, 1, 0, 0, 0);// 月份从0开始

		Calendar date2 = Calendar.getInstance();

		date2.set(2008, 5, 20, 0, 0, 0);



		while (date2.compareTo(date1) >= 0) {

			System.out.println(date1.get(Calendar.YEAR) + "-"

					+ (date1.get(Calendar.MONTH) + 1) + "-"

					+ date1.get(Calendar.DATE));

			date1.add(Calendar.DATE, 1);

		}

	}

}



<head> 

<title> </title>

</head> 



<body>



<script>

/**

* 时间对象的格式化;

*/

Date.prototype.format = function(format){

 /*

  * eg:format="YYYY-MM-dd hh:mm:ss";

  */

 var o = {

  "M+" :  this.getMonth()+1,  //month

  "d+" :  this.getDate(),     //day

  "h+" :  this.getHours(),    //hour

      "m+" :  this.getMinutes(),  //minute

      "s+" :  this.getSeconds(), //second

      "q+" :  Math.floor((this.getMonth()+3)/3),  //quarter

      "S"  :  this.getMilliseconds() //millisecond

   }

  

   if(/(y+)/.test(format)) {

    format = format.replace(RegExp.$1, (this.getFullYear()+"").substr(4 - RegExp.$1.length));

   }

 

   for(var k in o) {

    if(new RegExp("("+ k +")").test(format)) {

      format = format.replace(RegExp.$1, RegExp.$1.length==1 ? o[k] : ("00"+ o[k]).substr((""+ o[k]).length));

    }

   }

 return format;

}

</script>

<script type="text/javascript"> 

var date1 = new Date("2006-12-01".replace(/-/g,"/"));

var date2 = new Date("2008-06-20".replace(/-/g,"/"));

while(date1.getTime() <= date2.getTime()){

	document.write(date1.format("yyyy-MM-dd") + "<br/>");

	date1.setDate(date1.getDate() + 1);

}

</script> 



</body> 

</html>