英文字母和數字混合的字符串對象，如何排序？

    String[] array = new String[] {

        "D1", "D11", "D12", "D13", "D2", "D3", "H", "F0", "h1", "h0", "f1",

        "F2", "d9", "1"

    };

    // 假设所有情况都是字母在前，数字在后

    Comparator<String> cmp = new Comparator<String>() {



      public int compare(String str1, String str2) {



        // 字母部分

        String alphabet1 = str1.replaceAll("\\d+$", "");

        String alphabet2 = str2.replaceAll("\\d+$", "");



        // 如果不想区分大小写，否则compareTo

        int cmpAlphabet = alphabet1.compareToIgnoreCase(alphabet2);

        if (cmpAlphabet != 0) {

          return cmpAlphabet;

        }



        // 数字部分

        String numeric1 = str1.replaceAll("^[a-zA-Z]+", "");

        String numeric2 = str2.replaceAll("^[a-zA-Z]+", "");

        if ("".equals(numeric1)) {

          // 即使numeric2也是空串也无所谓，当然，如果比较的不是String（或其他immutable对象）则另当别论

          return -1;

        }

        if ("".equals(numeric2)) {

          return 1;

        }

        int num1 = Integer.parseInt(numeric1);

        int num2 = Integer.parseInt(numeric1);

        return num1 - num2;

      }

    };

    Arrays.sort(array, cmp);



    System.out.println(Arrays.toString(array));

  }

String ss[] = {"D12","D2","D03","B","D11","D8","D12","H","F0"};

		Arrays.sort(ss);

		for(String s : ss){

			System.out.print(s+",");

		}