散分！c#中用XslCompiledTransform解释一个xml用一个xslt时，没用的xml数据如何不输出？

hwbox 2010-12-30 11:08:15

我有一个xml和一个xslt在服务器端用XslCompiledTransform解释，想输出前5个，结果后面没有用的2个内容也出来了，只是没有格式，怎么才能让6、7两个节点不输出？



            string xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?> " + "\r\n"

                + "<NewDataSet>" + "\r\n"

                + "<Table>" + "\r\n"

                + "<Code>1</Code>" + "\r\n"

                + "<Desc>Good</Desc>" + "\r\n"

                + "</Table>" + "\r\n"

                + "<Table>" + "\r\n"

                + "<Code>2</Code>" + "\r\n"

                + "<Desc>New</Desc>" + "\r\n"

                + "</Table>" + "\r\n"

                + "<Table>" + "\r\n"

                + "<Code>3</Code>" + "\r\n"

                + "<Desc>New</Desc>" + "\r\n"

                + "</Table>" + "\r\n"

                + "<Table>" + "\r\n"

                + "<Code>4</Code>" + "\r\n"

                + "<Desc>New</Desc>" + "\r\n"

                + "</Table>" + "\r\n"

                + "<Table>" + "\r\n"

                + "<Code>5</Code>" + "\r\n"

                + "<Desc>New</Desc>" + "\r\n"

                + "</Table>" + "\r\n"

                + "<Table>" + "\r\n"

                + "<Code>6</Code>" + "\r\n"

                + "<Desc>New</Desc>" + "\r\n"

                + "</Table>" + "\r\n"

                + "<Table>" + "\r\n"

                + "<Code>7</Code>" + "\r\n"

                + "<Desc>New</Desc>" + "\r\n"

                + "</Table>" + "\r\n"

                + "</NewDataSet>" + "\r\n";



            xslt = "<xsl:stylesheet xmlns:xsl=\"http://www.w3.org/1999/XSL/Transform\" xmlns:msxsl=\"urn:schemas-microsoft-com:xslt\" version=\"1.0\" >" + "\r\n"

               + "<xsl:output method=\"html\"/>"

               + "<xsl:template match=\"/\">" + "\r\n"

               + " <html><body><P>"

               + "    <xsl:for-each select=\"NewDataSet/Table[position()<6]\">" + "\r\n"

               + "      <p>" + "\r\n"

               + "        <xsl:value-of select=\"Code\"/>" + "\r\n"

               + "      </p>" + "\r\n"

               + "    </xsl:for-each>" + "\r\n"

               + " </P></body></html>"

               + "</xsl:template>" + "\r\n"

               + "</xsl:stylesheet> " + "\r\n";

//略

            XsltTr.Transform(xmlDoc, null, outStreamWriter);



            string theHtml = System.Text.Encoding.UTF8.GetString(outmemoryStream.ToArray(), 0, outmemoryStream.ToArray().GetLength(0));



            context.Response.Write(theHtml);

我想要这样的结果



<html xmlns:msxsl="urn:schemas-microsoft-com:xslt">

  <body>

    <P>

      <p>1</p>

      <p>2</p>

      <p>3</p>

      <p>4</p>

      <p>5</p>

    </P>

  </body>

</html>

结果出来的是这个



<html xmlns:msxsl="urn:schemas-microsoft-com:xslt">

  <body>

    <P>

      <p>1</p>

      <p>2</p>

      <p>3</p>

      <p>4</p>

      <p>5</p>

    </P>

  </body>

</html>Code>

<Desc>New</Desc>

</Table>

<Table>

<Code>4</Code>

<Desc>New</Desc>

</Table>

<Table>

<Code>5</Code>

<Desc>New</Desc>

</Table>

<Table>

<Code>6</Code>

<Desc>New</Desc>

</Table>

<Table>

<Code>7</Code>

<Desc>New</Desc>

</Table>

</NewDataSet>