字符串处理、格式转换。。。求好的方法

噢噢噢噢 2011-04-17 01:34:58

原格式[]内的是毫秒现在想把[]内的数字替换成标准的lrc格式的分:秒:毫秒
原格式：



[ar:Michael Jackson]

[ti:Beat it]

[1090] Beat It 避开!

[3230] 谨以此歌告诫年轻的朋友避免不必要的麻烦

[8650] 暴力不能解决一切问题，只会伤害到自己

[12770] 制作人：河洲

[20610] 1st Verse They Told Him 他们告诉他： 　　

[40160] Don't You Ever Come Around Here “你胆敢再来？ 　　

[42720] Don't Wanna See Your Face You Better Disappear 你最好消失！

[45840] The Fire's In Their Eyes 怒火在他们眼中升腾

[48340] And Their Words Are Really Clear 话语也说得格外明白

目的格式：



[ar:Michael Jackson]

[ti:Beat it]

[00:01.09]Beat It 避开!

[00:03.23]谨以此歌告诫年轻的朋友避免不必要的麻烦

[00:08.65]暴力不能解决一切问题，只会伤害到自己

[00:12.77]制作人：河洲

[00:20.61]1st Verse] They Told Him 他们告诉他： 　　

[00:40.16]Don't You Ever Come Around Here “你胆敢再来？ 　　

[00:42.72]Don't Wanna See Your Face, 不想再见你， 　　

[00:43.98]You Better Disappear 你最好消失！

[00:45.84]The Fire's In Their Eyes 怒火在他们眼中升腾

[00:48.34]And Their Words Are Really Clear 话语也说得格外明白

...全文

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噢噢噢噢 2011-04-17

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以解决，结贴给分走人

CppCoder 2011-04-17

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把[]中的内容读的一个变量，处理变量，把结果放回[]中

太乙 2011-04-17

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用什么不重要，你windows下一样编译运行[Quote=引用 11 楼 ilyysys 的回复:]

楼上用的linux？
[/Quote]

太乙 2011-04-17

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$ g++ test.cpp //这里编译

$ ./a.out txt new_txt//这里运行

$ cat new_txt //查看运行后的结果输出文件

[ar:Michael Jackson]

[ti:Beat it]

[00:01.09] Beat It 避开!

[00:03.23] 谨以此歌告诫年轻的朋友避免不必要的麻烦

[00:08.65] 暴力不能解决一切问题，只会伤害到自己

[00:12.77] 制作人：河洲

[00:20.61] 1st Verse They Told Him 他们告诉他： 　　

[00:40.16] Don't You Ever Come Around Here “你胆敢再来？ 　　

[00:42.72] Don't Wanna See Your Face You Better Disappear 你最好消失！

[00:45.84] The Fire's In Their Eyes 怒火在他们眼中升腾

[00:48.34] And Their Words Are Really Clear 话语也说得格外明白

噢噢噢噢 2011-04-17

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楼上用的linux？

太乙 2011-04-17

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#include <iostream>

#include <string>

#include <fstream>

using namespace std;

string format(int num)

{

	num = num/10;

	int i = num%100;

	num = num/100;

	int j = num%100;

	num = num/100;

	int k = num%100;

	char buf[100];

	sprintf(buf, "%02d:%02d.%02d", k, j, i);

	return buf;

}

int main(int argc, char* argv[])

{

	ifstream ifs(argv[1]);

	ofstream ofs(argv[2]);

	string line;

	char buf[1024];

	int num;

	while (getline(ifs, line))

	{

		if (sscanf(line.c_str(), "[%d]%[^\n]", &num, buf) != 2)//这个地方改下

		{

			ofs << line << endl;

		}

		else

		{

			ofs << "[" << format(num) << "]" << buf << endl;

		}

	}

	return 0;

}

太乙 2011-04-17

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~/test$ cat txt

[ar:Michael Jackson]

[ti:Beat it]

[1090] Beat It 避开!

[3230] 谨以此歌告诫年轻的朋友避免不必要的麻烦

[8650] 暴力不能解决一切问题，只会伤害到自己

[12770] 制作人：河洲

[20610] 1st Verse They Told Him 他们告诉他： 　　

[40160] Don't You Ever Come Around Here “你胆敢再来？ 　　

[42720] Don't Wanna See Your Face You Better Disappear 你最好消失！

[45840] The Fire's In Their Eyes 怒火在他们眼中升腾

[48340] And Their Words Are Really Clear 话语也说得格外明白 

~/test$ ./a.out txt new_txt

~/test$ cat new_txt 

[ar:Michael Jackson]

[ti:Beat it]

[00:01.09]Beat

[00:03.23]谨以此歌告诫年轻的朋友避免不必要的麻烦

[00:08.65]暴力不能解决一切问题，只会伤害到自己

[00:12.77]制作人：河洲

[00:20.61]1st

[00:40.16]Don't

[00:42.72]Don't

[00:45.84]The

[00:48.34]And

stain_less 2011-04-17

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只能自己写一个方法来转换，很简单吧。

太乙 2011-04-17

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#include <iostream>

#include <string>

#include <fstream>

using namespace std;

string format(int num)

{

	num = num/10;

	int i = num%100;

	num = num/100;

	int j = num%100;

	num = num/100;

	int k = num%100;

	char buf[100];

	sprintf(buf, "%02d:%02d.%02d", k, j, i);

	return buf;

}

int main(int argc, char* argv[])

{

	ifstream ifs(argv[1]);

	ofstream ofs(argv[2]);

	string line;

	char buf[1024];

	int num;

	while (getline(ifs, line))

	{

		if (sscanf(line.c_str(), "[%d]%s", &num, buf) != 2)

		{

			ofs << line << endl;

		}

		else

		{

			ofs << "[" << format(num) << "]" << buf << endl;

		}

	}

	return 0;

}